[ale] Converting C data structures to Perl

[Chris Fowler]

Maybe I'm doing something wrong with it,  Because even if I simplify
down to an array of hashes like this,

%device1 = {
    ip => "192.168.2.231",
    name => "bubba",
    pass => "password",
};
%device2 = {
    ip => "192.168.2.231",
    name => "bubba",
    pass => "password",
};
@unit = (%device1, %device2);

print $array[0]{name};

I do not get a name displayed.


On Mon, 2003-04-21 at 20:57, Fletch wrote:
> >>>>> "Christopher" == Christopher Fowler <cfowler at outpostsentinel.com> writes:
> 
>     Christopher> Hello,
> 
>     Christopher> I've got my data parsed and having a issue try to
>     Christopher> make it accessible throughout the program.
> 
> Erm, if it's parsed in perl then why are you talking about C
> structures . . . /me is confuzlled . . .
> 
>     Christopher> Here is a refernce in C
> 
>     Christopher> struct device { char *name; char *user; char *pass; }
> 
>     Christopher> struct unit { char ip; struct device **d; };
> 
>     Christopher> struct unit **unit; // Array of units
> 
> If you really do have it as C pointery-fun data you could use unpack
> and some deep wizardry, but for something as involved as this it'd
> probably be much easier to write your own API using either XS or
> Inline::C.  Start with perldoc perlxstut and perldoc perlxs for the
> former, or look for the Inline documentation on search.cpan.org for
> the later (which might be easier to pick up).
> 
> 
> -- 
> Fletch                | "If you find my answers frightening,       __`'/|
> fletch at phydeaux.org   |  Vincent, you should cease askin'          \ o.O'
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>                       |                                               U
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