[ale] perl question

[Derek Atkins]

Geoffrey Myers <lists at serioustechnology.com> writes:

> Oh the loop works as defined, it's just that the value is not passed to 
> the sub bar()  My expectation was that since the call to bar() was 
> inside the loop, that $foo would be accessible within the sub.

Alas, it doesn't work that way.  PERL doesn't scope variables that way.
You would need to define a global and assign it, or you would need to
pass it as a variable to the sub.

-derek

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       Derek Atkins, SB '93 MIT EE, SM '95 MIT Media Laboratory
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