[ale] Android dialer issues and solutions
Narahari 'n' Savitha
savithari at gmail.com
Sat Jun 25 10:54:54 EDT 2011
How can I program it differently ? Isnt there a dialer off the shelf that
does this ?
If I need to program differently, where should I get started
On Sat, Jun 25, 2011 at 12:40 AM, Michael Trausch <mike at trausch.us> wrote:
> Most likely because they just look at the phone number section. It could be
> programmed to do differently (and the wonderful thing is that you can).
>
> I think the best solution, though, would be an application that abstracts
> the calling card bit for you, and simply puts the real phone number in the
> call log. Bonus points for intercepting int'l calls and routing them via the
> calling card...
>
> --
> Sent from my phone... a G2 running CM7 nightlies!
> On Jun 24, 2011 11:34 PM, "Narahari 'n' Savitha" <
> savithari at gmail.com> wrote:
> > Well iPhone 3 fixed. It is not that hard after all
> >
> > The number to uncle is
> >
> > 18182004622,,061822#,011018242538588#
> >
> > The number to Mom is
> >
> > 18182004622,,061822#,011018242538544#
> >
> >
> > If the dialer looks only till the "," then its an issue, instead if all
> the
> > numbers are looked at then it is unique and they can report off of that.
> >
> > But the dialers dont do that, no idea why they do that.
> >
> > -Narahari
> >
> > On Fri, Jun 24, 2011 at 1:53 PM, Michael B. Trausch <mike at trausch.us>
> wrote:
> >
> >> On Fri, 2011-06-24 at 13:49 -0400, Narahari 'n' Savitha wrote:
> >>
> >> > Right I tried what you said and disconnected right away and the call
> >> > logs looks right.' With calling card in the picture it messes up.
> >> > Any solution ?
> >>
> >> Yes, if you have no problem with obtaining the source code and patching
> >> it to deal with that in some way. The thing is this: there really is no
> >> way for the Dialer application (which is the same application that shows
> >> the call logs) to know that the number that you're dialing is a calling
> >> card. It records the number that you dialed, because that's what it's
> >> supposed to do. Once the line is connected, everything after that is
> >> essentially opaque.
> >>
> >> There are a few possibilities that I can think of that would work around
> >> *some* instances of this problem, but I can think of no solution that
> >> would work universally and completely without messing something up.
> >>
> >> --- Mike
> >>
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