[ale] cron entry that runs the 2nd saturday of every month

[Michael H. Warfield]

On Fri, 2011-08-26 at 19:33 -0400, David Tomaschik wrote: 
> On 08/26/2011 03:38 PM, Geoffrey Myers wrote:
> > Lightner, Jeff wrote:
> >> When I had to do this back in 2008 on HP-UX I worked out a script
> >> that relied on the cal (calendar) command.
> >>
> >> The following command line will give you the 2nd Saturday of the
> >> month:
> >>
> >> cal |cut -c19-20 |grep '[0-9]'|head -2 |tail -1
> >>
> >> The following command will give you today's day of month: date +%d
> > Doing something similar only relying on date alone:
> >
> > date +%d
> > date +%u

> If you have cron run every Saturday, the %u is unnecessary.  (You know
> it's Saturday.)  Then just compare to the range [8-14].  No cal needed. 
> (Might be what you're doing already.)

Even when you KNOW it's best to CONFIRM.

Short cut...

CODE=`date +%u%d`

if [[ $CODE -gt 607 && -lt 615 ]]
then
# Do it.
else
# Don't do it..
fi

If it's not on Saturday, the test fails.  If it is on Saturday (%u = 6)
then the day has to be between 07 and 15.

Seems simple enough to me.

Regards,
Mike
-- 
Michael H. Warfield (AI4NB) | (770) 985-6132 |  mhw at WittsEnd.com
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