[ale] Bash question...

[Ken Alexander]

My bad. I thought I remembered using real numbers with ((  )). I was
wrong, only int's ...

sorry !

On Mon, 2007-07-23 at 09:57 -0400, James P. Kinney III wrote:

> On Mon, 2007-07-23 at 05:51 -0400, Brian J. Dowd wrote:
> > Thanks for the suggestion, Ken.
> > -B
> > > You can use the arithmetic expression operator  - ((  )) 
> > >
> > > if (( $var < -4 )) ; then
> 
> 
> Hmm. doesn't work for me...
> 
> [jkinney at merlin ~]$ bash -version
> GNU bash, version 3.2.9(1)-release (x86_64-redhat-linux-gnu)
> Copyright (C) 2005 Free Software Foundation, Inc.
> [jkinney at merlin ~]$ var=-4.3; if (( $var < -4 )); then echo "less"; else
> echo "more"; fi
> bash: ((: -4.3 < -4 : syntax error: invalid arithmetic operator (error
> token is ".3 < -4 ")
> more
> [jkinney at merlin ~]$ 
> 
> 
> Doesn't like the decimal place.
> 
> > > ..
> > > fi
> > > On Sun, 2007-07-22 at 10:37 -0400, Dr. Brian J. Dowd wrote:
> > >> The value of $var is -4.865876
> > >>
> > >> if [ $var -lt "-4" ];
> > >>
> > >> throws an "Integer expression expected" error
> > <snip>
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> > 
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