[ale] Bash: How to determine if called from cron?

[Christopher Fowler]

If you did do FD!=`perl <<EOF
EOF
`

Then I think stdout would be a pipe that your script created.  So that
might be a problem.


On Mon, 2005-06-27 at 08:39, Christopher Fowler wrote:
> Cron output is stored into a temp file in /tmp.  You can stat STDOUT and
> see what filename is for that descriptor.  If the filename contains the
> word 'cron' then you are inside cron. 
> 
> The only problem there is I know how to do this in C.  Uoi can do it in
> perl but I have no clue how to in bash.
> 
> You might be able to do something like this:
> 
> LOCATION=`perl <<EOF
> ......
> EOF
> `
> 
> Then check the value of that variable.
> 
> Or maybe this will work in bash
> 
> [cfowler at cfowler cfowler]$ FD1=`ls -l /proc/$$/fd/1 | cut -d '>' -f2`;
> [cfowler at cfowler cfowler]$ echo $FD1
> /dev/pts/1
> 
> You'll want to check FD1 for the word cron.  
> 
> 
> On Mon, 2005-06-27 at 00:17, Christopher Bergeron wrote:
> > Does anyone know of an easy way for my script to determine if it's being 
> > run from cron or from a user shell? 
> > 
> > I have a feeling theres an easy way to do this, but I'm drawing a 
> > complete blank right now.  I'm looking at my Environment vars, but I'm 
> > not sure what gets set by Cron when it runs a script.
> > 
> > Any ideas are much appreciated...
> > 
> > Kind regards,
> > CB
> > 
> > 
> > _______________________________________________
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> > Ale at ale.org
> > http://www.ale.org/mailman/listinfo/ale
> 
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