[ale] Shell Scripting question

[nick travis]

Nevermind, I just figured it out, i was able to use egrep Example:
results | cat -b10-

On Wed, 2003-08-06 at 14:53, nick travis wrote:
> thanks for the help, what can I use to get the last three words off of a
> line, instead of just the last word?
> 
> On Wed, 2003-08-06 at 13:53, Geoffrey wrote:
> > nick travis wrote:
> > > Here's the exact line in the file, I want to pull out the file name from
> > > it.
> > > VIOLATION  : PAM service rlogin (/etc/pam.d/rlogin) does not have module
> > > pam_shells.so for module type auth.
> > > ...ACTION  : Add module pam_shells.so for module type auth to PAM
> > > service rlogin (/etc/pam.d/rlogin).
> > > Example: auth     required    /lib/security/pam_shells.so
> > > 
> > > there will be several violations like this in the file, but the file
> > > name will start at a different location each time.  since the violation
> > > will be in a different file.
> > 
> > Well, that message contains three different references to file names, 
> > but you can get to all of them with the right tool.  If for example you 
> > want the name that's contained between the parans, you can use awk:
> > 
> > awk -F '[()]' '{print $2}' intputfile
> > 
> > The above will retreive the first occurance of /etc/pam.d/rlogin. 
> > Basically you're telling awk that there are two field separators and 
> > they are the parans.  Therefore, the file name would be the second field.
> > 
> > Same solution would apply for the second /etc/pamd./rlogin entry, you'd 
> > just have to adjust the '$2' appropriately.
> > 
> > The last file reference (/lib/security/pam_shells.so) can be had by the 
> > previous posted solution:
> > 
> > awk '{print $NF}' inputfile
> > 
> > 
> > NF in awk is the number of fields, therefore $NF is the last field value.
> 
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