[ale] Shell: dir name

[Chris Coleman]

dirname can be used to strip off the file name and leave the directory name. In a BASH shell, $0 is used to represent the path and name of the file being executed. Therefore I can use:

  dir_name=$(dirname $0)

in side of the script to find out what directory the script was executed from.

Chris Coleman
-----Original Message-----
From: Joseph A Knapka [mailto:jknapka at earthlink.net]
To: ale at ale.org
Sent: Tuesday, May 21, 2002 9:50 AM
To: Zyman, Andy
Cc: 'ale at ale.org'
Subject: Re: [ale] Shell: dir name


"Zyman, Andy" wrote:
> 
> Hello,
> i have simple question. but i somehow stuck on it.
> 
> I need to find out from which dir. the scripts was executed.
> here is an example:
> cat /tmp/staff/script.sh
> #!/bin/ksh
> SPOOL_FILE=$PWD/log/spool_file.log
> echo $SPOOL_FILE
> #END
> 
> After "manual" executing , the output is:
> /tmp/staff/log/spool_file.log
> 
> this was working perfectly well until i cronned it.
> 
> now in the output i basically have :
> $HOME/log/spool_file.log
> 
> I thought there is an env. var which will point to the dir. The only one
> thing i found is $_. But it returns ( in case of ksh ) the whole
> path/script_name. And i just need  dir. Any help?

I don't think there is such a variable (though I may be wrong).
But in your cron job, you could explicitly change to the
directory you want to exec the script from:

0 0 * * * ( cd /tmp/staff ; . ./script.sh )

-- Joe
   Looking for a .sig...

---
This message has been sent through the ALE general discussion list.
See http://www.ale.org/mailing-lists.shtml for more info. Problems should be 
sent to listmaster at ale dot org.


---
This message has been sent through the ALE general discussion list.
See http://www.ale.org/mailing-lists.shtml for more info. Problems should be
sent to listmaster at ale dot org.