[ale] Re: foreign key?

[Jim Philips]

Apparently, Contributor_ID is in both tables. You need something like:

...where Item.Contributor_ID>1


On Fri, 2002-01-25 at 13:13, David S. Jackson wrote:
> On Fri, Jan 25, 2002 at 12:33:59PM -0500 Gurhan Ozen <c-gurhan.ozen at wcom.com> wrote:
> > Hi David,
> > First of all, whever you have a primary key on your table, do all updates
> > according to the primary key..
> >  So whatever the primary key for the person you wanna do update, do
> > something like:
> >  update Contributors set Contact_ID = 1, Volunteer_ID = 13 where
> > Contributor_ID=number;
> > Also since the columns are integer data type, don't use quotes around them.
> >  I hope this helps..
> 
> Yep, I removed the quotes, and it worked.
> 
> Here's another problem:  I think I'm doing an unintentional
> ambiguous select:
> 
> mysql> select Item.Item_Description, Item.Retail_Value,
> Item.Bid_Description, Contributors.Name from Item, Contributors
> where Contributor_ID > 1;
> 
> I get the error:
> 
> ERROR 1052: Column: 'Contributor_ID' in where clause is ambiguous
> 
> So, looking again at my definitions for Contributor_ID in both
> tables, I see they aren't exactly alike.  Is there a way I can
> make Contributor_ID in Item refer back to the Index
> (Contributor_ID) in Contributors?  I gather that just making the
> data types the same is not enough?
> 
> TIA!
> 
> -- 
> David S. Jackson                        dsj at dsj.net
> =-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
> I'm going to live forever, or die trying!
> 		-- Spider Robinson
> 
> ---
> This message has been sent through the ALE general discussion list.
> See http://www.ale.org/mailing-lists.shtml for more info. Problems should be 
> sent to listmaster at ale dot org.
> 



---
This message has been sent through the ALE general discussion list.
See http://www.ale.org/mailing-lists.shtml for more info. Problems should be 
sent to listmaster at ale dot org.