[ale] foreign key?
David S. Jackson
deepbsd at earthlink.net
Fri Jan 25 11:48:31 EST 2002
Hi,
I'm trying to update the values of Contact_ID and
Volunteer_ID in a table called Contributors. The layout for
Contributors is
+----------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra
|
+----------------+--------------+------+-----+---------+----------------+
| Contributor_ID | tinyint(3) | | PRI | 0 |
auto_increment |
| Name | varchar(100) | | | |
|
| Street_Address | varchar(50) | YES | | NULL |
|
| City | varchar(20) | YES | | NULL |
|
| State | varchar(5) | YES | | NULL |
|
| Zip | mediumint(8) | YES | | NULL |
|
| Contact_ID | tinyint(3) | YES | | NULL |
|
| Volunteer_ID | tinyint(3) | YES | | NULL |
|
+----------------+--------------+------+-----+---------+----------------+
I'm using the command:
update Contributors set Contact_ID = "1", Volunteer_ID = '13'
where Name = "Somebody Lastname";
After having issued the command, I get
Query OK, 0 rows affected (0.00 sec)
Rows matched: 0 Changed: 0 Warnings: 0
But then when I select * in Contributors where Name = "Somebody
Lastname"; The values haven't been updated. They remain 0
and 0.
What gives? Is this a foreign key problem?
TIA.
PS. Oh yeah, I'm using mysql 3.22 on debian 2.2.
--
David S. Jackson dsj at dsj.net
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
The other day I... uh, no, that wasn't me.
-- Steven Wright
---
This message has been sent through the ALE general discussion list.
See http://www.ale.org/mailing-lists.shtml for more info. Problems should be
sent to listmaster at ale dot org.
More information about the Ale
mailing list