Friends:<br><br>I want to forward port 19080 to 8080 on my local arch box ? <br><br>Is there a simple way to do this. I googled it and I see something called iptables but it is too hairy to learn.<br><br>Can any expert here break it down for me as to what all is involved.<br>
<br>I should be able to say traffic on port 19080 forward to port 8080 on the same ip.<br><br>My ifconfig results are<br><br><span style="font-family:courier new,monospace">[devusr@ARCH64-TOMCAT-DEV-MACHINE WEB-INF]$ ifconfig<br>
enp0s3: flags=4163<UP,BROADCAST,RUNNING,MULTICAST> mtu 1500<br> inet 10.0.2.15 netmask 255.255.255.0 broadcast 10.0.2.255<br> inet6 fe80::a00:27ff:fea6:8c98 prefixlen 64 scopeid 0x20<link><br>
ether 08:00:27:a6:8c:98 txqueuelen 1000 (Ethernet)<br> RX packets 128271 bytes 36766353 (35.0 MiB)<br> RX errors 0 dropped 0 overruns 0 frame 0<br> TX packets 99743 bytes 11777820 (11.2 MiB)<br>
TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0<br><br>lo: flags=73<UP,LOOPBACK,RUNNING> mtu 65536<br> inet 127.0.0.1 netmask 255.0.0.0<br> inet6 ::1 prefixlen 128 scopeid 0x10<host><br>
loop txqueuelen 0 (Local Loopback)<br> RX packets 25378 bytes 38050755 (36.2 MiB)<br> RX errors 0 dropped 0 overruns 0 frame 0<br> TX packets 25378 bytes 38050755 (36.2 MiB)<br> TX errors 0 dropped 0 overruns 0 carrier 0 collisions 0</span><br>
<br>-Narahari<br>